Question

Example 4: In Fig. 8.22, ABCD is a quadrilateral and BEI AC
and also BE meets DC produced at E. Show that area of A ADE
is equal to the area of the quadrilateral ABCD.
Solution: Observe the figure carefully.
ABAC and AEAC lie on the same base AC and between the
same parallels AC and BE.
Therefore, ar(BAC) = ar(EAC)
(By The
So, ar(BAC) + ar(ADC) = ar(EAC) + ar(ADC) (Adding same a
ar(ABCD) = ar(ADE)
or
EXERCISE 8.3
1.
In Fig.8.23, E is any point on median AD of a AABC.
Show that ar(ABE) = ar (ACE).​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

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