Question

Example 4: Is 1188 a perfect cube? If not, by which smallest natural number should
1188 be divided so that the quotient is a perfect cube?

Answer 1

1188 = 2×2×3×3×3×11

The primes 2 and 11 do not appear in groups of three. • So, 1188 is not a perfect cube. In the factorisation of 1188, the prime 2 appears only two times and the prime 11 appears once.

So, if we divide 1188 by 2 2 11 = 44, then the prime factorisation of the quotient will not contain 2 and 11.

Hence the smallest natural number by which 1188 should be divided to make it a perfect cube is 44.

And the resulting perfect cube is 1188 44=27=3³