Question

Example 4. The angle of elevation of
the top of a tower from a point on the ground,
which is 30 m away from the foot of the tower,
is 30°. Find the height of the tower.​

Answer 1

Answer:

Tan 30=1/ 1.732

h/30=1/1.732

H=30/1.732

h=17.32

Answer 2

Answer:

In ∆ ABC,

tan ∅ = Perpendicular/Height

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.