Example 5.27
The orbit of Halley's Comet (Fig. 5.51) is an ellipse 36.18 astronomical units long and by 9.12
astronomical units wide. Find its eccentricity.
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Given : The orbit of Halley's Comet is an ellipse 36.18 astronomical units long and by 9.12 astronomical units wide
To find : eccentricity
Solution:
orbit of Halley's Comet is an ellipse
2a = 36.18 => a = 18.09
2b = 9.12 => b = 4.56
c² = a² - b²
=> c² = 18.09² - 4.56²
=> c = 17.5
e = c/a
=> e = 17.5/18.09
=> e = 0.967
=> e = 0.97
eccentricity = 0.97
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