Physics, asked by jaswantsivaratri9, 5 months ago

Example 5.6 See Fig. 5.8. A mass of 6 kg
is suspended by a rope of length 2 m
from the ceiling. A force of 50 N in the
horizontal direction is applied at the mid-
point P of the rope, as shown. What is the
angle the rope makes with the vertical in
equilibrium ? (Take g = 10 m s). Neglect
the mass of the rope.​

Answers

Answered by kinjon
0

Answer:

For horizontal equilibrium-

T

3

=T

1

sinθ

For vertical equilibrium-

T

2

=T

1

cosθ

Taking ratios-

T

2

T

3

=tanθ

And for equilibrium of body T

2

=6kgwt=6×10=60N

⟹tanθ=

6

5

or θ=tan

−1

6

5

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