Example 5.6 See Fig. 5.8. A mass of 6 kg
is suspended by a rope of length 2 m
from the ceiling. A force of 50 N in the
horizontal direction is applied at the mid-
point P of the rope, as shown. What is the
angle the rope makes with the vertical in
equilibrium ? (Take g = 10 m s). Neglect
the mass of the rope.
Answers
Answered by
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Answer:
For horizontal equilibrium-
T
3
=T
1
sinθ
For vertical equilibrium-
T
2
=T
1
cosθ
Taking ratios-
T
2
T
3
=tanθ
And for equilibrium of body T
2
=6kgwt=6×10=60N
⟹tanθ=
6
5
or θ=tan
−1
6
5
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