Question

Example 5 A5 m long ladder is placed leaning towards a vertical wall such that it
reaches the wall at a point 4 m high. If the foot of the ladder is moved 16 m towards
the then find the distance by which the top of the ladder would slide upwards on
The
is the base of wall.​

Answer 1

Actually question was wrong it's not 16 m it's 1.6m

By Pythagoras theorem

Base ^2= 5^2-4^2

= 25-16 = 9 Base= √9 = 3cm.

New base would be 3-1.6=1.4 m

By Pythagoras Perpendicular^2= 25-1.96

= 23.04 =√23.04 = 4.8m

Length of ladder that was moved upwards = 4.8-4 = 0.8m

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