Question

Example 5 : Determine the AP whose 3rd term is 5, and the 7th term is 9. Solution : We have a, = a + (3 - 1) d = a + 2d = 5 nd a, = a + (7 - 1) d = a + 6d = 9​

Answer 1

Answer:

We know that an = a + (n – 1)d From (1) & (2) 5 – 2d = 9 – 6d 6d – 2d = 9 – 5 Given 3rd term is 5 a3 = a + (3 – 1)d 5 = a + 2d a = 5 – 2d Given 7th term is 9 a7 = a + (7 – 1)d 9 = a + 6d a = 9 – 6d 4d = 4 d = 4/4 d = 1 Putting d = 1 in (1) a = 5 – 2d a = 5 – 2(1) a = 5 – 2 a = 3 Hence , First term of an A.P = 3 Second ...

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