Question

Example 5. Draw a histogram from the following series:
1-10
11-20
21-30
Marks Obtained
No. of Students
31-40
41-50
10
14
20
12
4
Solution:
In the given example, the difference between the upper limit of a class-interval and lower limit of the next
class-interval is 1. So, 0.5 (half of 1) will be subtracted from the lower limits of all the classes and added to
the upper limits. The adjusted classes would then be as shown in the following table:
0.5-10.5
10.5-20.5
20.5–30.5
30.5–40.5
40.5-50.5
Marks Obtained
No. of Students
10
14
20
12
4​

Answer 1

Answer:

vaishnavi

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Explanation:

ANSWER

The class intervals are all equal with length of 10 marks. Let us donate these class intervals along the X-axis. Denote the number of students along the Y-axis, with appropriate scale. The histogram is given below.