Example 5: Three metallic cubes of sides 4 cm, 3 cm,
and 5 cm are melted and recast into a new cube. Find
the edge of the new cube so formed.
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(3 metallic cubes) ⟶ (New cube)
3 metallic cubes of sides 4 cm, 3 cm, 5 cm.
Let the sides of cubes be (a₁), (a₂) and (a₃) respectively.
Volume of first cube = (a₁)³
⇒ Volume of first cube = 4³
∴ Volume of first cube = 64 cm³
Volume of second cube = (a₂)³
⇒ Volume of second cube = 3³
∴ Volume of second cube = 27 cm³
Volume of third cube = (a₃)³
⇒ Volume of third cube = 5³
∴ Volume of third cube = 125 cm³
These 3 cubes are melted and recast into a new cube
So, Volume of new cube = Sum of volumes of 3 cubes
Volume of new cube = 64 + 27 + 125 cm³
⇒ Volume of new cube = 216 cm²
Now let's find the edge of new cube so formed.
Volume of new cube = (Edge)³
→ 216 = (Edge)³
→ (Edge)³ = 216
→ Edge = ∛216
→ Edge = ± 6 cm
Side of cube cannot be negative.
∴ Edge = 6 cm
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