Example 53. Calculate the electric field due to an electric
dipole of length 10 cm having charges of 1 uC at an equatorial
point 12 cm from the centre of the dipole.
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Therefore the Electric field due to an electric dipole is 4.1 × 10^5 N/C.
Given : An electric dipole of length 10cm having charge of one micro coulomb at an equatorial point 12cm from the centre of the dipole.
To find : The electric field due to the electric dipole.
solution : The electric field due to an electric dipole is given by, E = KP/(r² + a²)³/²
where P = q2a = 10^-6 C × 10 × 10^-2 m = 10^-7 Cm
r = 12 cm = 0.12 m and a = 5cm = 0.05 m
The electric field, E = (9 × 10^9 × 10^-7)/[(0.12)² + (0.05)²]³/²
= (900)/[0.0144 + 0.0025]³/²
= 900/(0.0169)³/²
= 900/(0.13)³
= 900/0.002197
= 409,649.522
≈ 4.1 × 10^5 N/C
Therefore the Electric field due to an electric dipole is 4.1 × 10^5 N/C.
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