Example 6 A die is thrown twice and the sum of the numbers appearing is observed
to be 6. What is the conditional probability that the number 4 has appeared at least
once?
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Step-by-step explanation:
Therefore, A = (1, 5), (2, 4), (3, 3), (4, 2), (5, 1). So as we see that there are 5 possible ways so that the sum of the numbers is 6. As we know that when two dice are thrown the possible number of cases are (6×6) = 36. Now let (E) be the event such that 4 appears once.
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