Example 6 : Find the LCM and HCF of 6 and 20 by the prime factorisation
Solution: We have : 6 = 21 x 31 and 20 = 2 x 2 x 5 = 22 x 51
You can find HCF(6, 20) = 2 and LCM6, 20) = 2 x 2 x 3 x 5 = 60, as done in
earlier classes.
Note that HCF(6, 20) = 21 = Product of the smallest power of each com
prime factor in the numbers.
LCM (6, 20) = 22 x 31 x 51 = Product of the greatest power of each prime
involved in the numbers.
From the example above, you might have noticed that HCF(6,20) LC
= 6 x 20. In fact, we can verify that for any two positive integers a
HCF (a, b) ~ LCM (a, b) = a × b. We can use this result to find the LCM
positive integers, if we have already found the HCF of the two positive inte
nmnle 7. Find the HCF of 96 and 404 by the prime factorisation method
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Answer:
lcm of 6 and 20 is 60
Explanation:
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