Physics, asked by kunalkoshal, 24 days ago

Example 6 : Find the value of 'g' on the surface of moon if an object of given mass having radius negligible to that of moon, is placed on it. Mass of moon, M = 7.4 x 10pawer22 kg Radius of moon, R = 1.75 x 10 pawer6 n Universal Gravitational Constant, G = 6.67 * 10power-11
Nm² kg-2​

Answers

Answered by sujata4312
0

Explanation:

On the surface of the moon, the distance to the center of mass is the same as the radius: r=1.74×10

6

m=17,40,000 m. The acceleration due to gravity on the surface of the moon can be found using the formula:

g=

r

2

GM

g=

17400000

(6.673×10

−11

)(7.4×10

22

)

The acceleration due to gravity on the surface of the moon is 1.620 ms

2

.

Answered by piyushkumar22009
0

Answer:

Combine the pairs of sentences using the conjunction given in the

brackets and rewrite them. The first one has been done for you.

1. I was ill. I had to work, (even though)

Even though I was ill I.had to work.

2. We call you. You never receive it. (But)

______________________________

3. You can go. You finish the work, (when)

______________________________/ when you finish the work, you can go.

4. They came to the party. They weren’t invited, (despite)

___________________________They weren’t invited, despite they came to

the party.

Explanation:

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