Question

Example 6. Find three consecutive even integers such that if the first is divided by 2, the second by 4 and the last by 2
then the sum of the quotients is 45.​

Answer 1

Let X, (X+1),(X+2) are 3Consecutive numbers

X/10 +(X+1)/17+(X+2)26=10

L.C.M=4420

(442(X)+260(X+1)+170(X+2)/4420=10

(442X+260x+260+170+340)=4420=10

(442x+260x+170x+269+340)=44200

872x +600 =44200

872x=44200-600

872x=43600

X=43600/872

X=50

1st no.(X)=50

2nd no. (x+1)=50+1=51

3rd no. (x+2)=50+2=52

The 3 consecutive numbers are 50,51,52

Hope this will help you......