Question

Example 6. Forces of 5√ 2 N and 6 V2 N are acting on a
body of mass 1000 kg at an angle to 60° to each other. Find
the acceleration, distance covered and the velocity of the
mass after 10 s.​

Answer 1

Solution :-

• F1 = 5√2 N

• F2 = 6√2 N

Resultant force acting on the object is given by ,

➽ F = √ F1² + F2² + 2F1F2 cosФ

➽ F = √25x2 + 36x2 +60x2 cos 60

➽ F = √ 50 + 64 + 120 x 1/2

➽ F = √50 + 64 + 60

➽ F = √174

➽ F = 13.2 N

Now in order to find acceleration let us apply Newton's Second Law of motion ,

➽ F = ma

➽ a = F / m

➽ a = 13.2 / 1000

➽ a = 0.0132 m / s²

As the body moves with uniform acceleration we can use the first kinematic equation in order to find the final velocity and second to find the distance traveled

By using the second kinematic equation ,

➽ s = ut + at² /2

As u =0 ,

➽ s = at² /2

➽ s = 0.0132 x 100 /2

➽ s = 1.32 / 2

➽ s = 0.6 m

Now by using the first kinematic equation ,

➽ v = u + at

➽ v = at  ( ∵ u =0 )

➽ v = 0.0132 x 10

➽ v = 0.132 m /s

The acceleration of the body is 0.0132 m /s ²

The distance covered by the body is 0.6 m

The final velocity of the body is 0.132 m /s