Question

Example 6. Forces of 52 N and 6 V2 N are acting on a
body of mass 1000 kg at an angle to 60° to each other. Find
the acceleration, distance covered and the velocity of the
mass after 10 s.

please draw an diagram ​

Answer 1

resultant force=( 6√2)² +(5√2)²+2*6√2*5√2*cos60=182N

F=M×A

A=F/M

A=182÷1000

=0.182m/s²

now,

V=U+A×T

V=0+0.182×10

V=1.82m/s

V=DISPLACEMENT/TIME

D=V×T

D=1.82×10

D=18.2m