Question

EXAMPLE 6. If 2 is a root of equation x2 + kx + 12 = 0 and the equation
(x2 + kx +q) = 0 has equal roots, find the value of q.​

Answer 1

Answer:

16

Step-by-step explanation:

given,

let f(x)=x²+kx²+12=0

g(x)=x²+kx+q=0

roots of g(x) are equal

2 is the root of f(x) so,

substitute x=2 in f(x)

2²+2k+12=0

k=-8 substitute in g(x)

x²-8x+q=0

roots are equal so

b²-4ac=0

[-8]²-4(1)(q)=0

64=4q

q=16

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Answer 2

Answer:q=12

Step-by-step explanation:if 2 is a root of equation X2+Kx+12=0

Then,p(2)=(2)^2+k(2)+12=0

=4+2k+12=0

=2k=-16

=K=-8

If X2+Kx+12=0 and X2+Kx+q=0 are equal,so we can put the value of k and the value of X on eq X2+Kx+q=0

=X2+Kx+q

=(2)^2+(-8)(2)+q=0

=4-16+q=0

=-12+q=0

q=12

You can use this method of the question is of 5 marks but if the question is of 1 mark so you can simply write that the both following equation are equal that's why q=12.

Hope it will help you