Question

Example-6. In APQR, right angle is at Q, PQ= 3 cm and PR = 6 cm. Determine ZQPR and
ZPRQ
P​

Answer 1

Answer:

ΔPQR; LQ=90

o

PQ=3cm; PR=6cm

QR=

6

2

−3

2

=3

3

sin(LQPR)=

PR

QR

=

6

3

3

=

2

3

So, LQPR=60

o

⇒ LQRP=30

o

.

Answer 2

Hello mate..

Here Is Your Answer:

GIVEN:

PQ = 3cm

PR = 6cm

∠Q = 90°

$\bold{Therefore, \frac{pq}{pr} = sin \: r \: or \: sin \: r \: = \frac{3}{6} }$

So, ∠PRQ = 30°

And therefore, ∠QPR = 60°

[NOTE: if one of the sides and any other part ( either an acute angle or any side) of a right angled triangle is known, the remaining sides and angles of the triangle can be determined]

HOPE THIS HELPS YOU..