Question

EXAMPLE 6 In one experiment, 6.54 g of iron(III) oxide was reduced with hydrogen to give 4.73 g of iron. In another experiment, 2.87 g of iron was heated and treated with steam when 3.97 g of iron(III) oxide was obtained. Show that these data illustrate the law of constant proportions.​

Answer 1

Answer:

Explanation:

In first experiment,

2.4 g of iron oxide gave 1.68 g of iron.

Mass of iron oxide =2.4 g

Mass of iron  =1.68 g

Mass of oxygen =2.4−1.68=0.72

Ratio of masses of iron and oxygen =  

0.72 /1.68

​

=7:3

In second experiment,

Mass of iron oxide =2.9 g

Mass of iron  =2.09 g

Mass of oxygen =2.9−2.09=0.81

Ratio of masses of iron and oxygen =  

0.81 /2.09  =7:3

The same ratio confirms that these experiments clarify Law of constant proportion.