Question

Example 6.
The length of a rectangular park exceeds its breadth by 17 metres. If the perimeter of
the park is 178 metres, find the dimensions of the park.
Let the breadth of the park be x metres​

Answer 1

Answer:

let the breadth be 'x'

let the length be 'x+17'

Perimeter of rectangle=2(l+b)

178=2(x+x+17)

178=2(2x+17)

178/2=2x+17

89=2x+17

89-17=2x

72=2x

72/2=x

36=x

36+17=x+17

53 =breadth

Step-by-step explanation:

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Answer 2

Given:-

• The length of a rectangular park exceeds its breadth by 17 meters.
• The perimeter of the park is 178 meter.

To find:-

• Find the length and breadth of the rectangular park ?

Solution:-

• Let the length of the park be 'L' m.
• Let the breadth of the park be 'B' m.

The length of a rectangular park exceeds its breadth by 17 meters.

According to question:-

=> L = B + 17 ........(i).

We know that,

The perimeter of rectangular park = 2(L + B)

=> 178 = 2(L + B)

=> 178 = 2(B + 17 + B)

=> 178 = 2(2B + 17)

=> 178 = 4B + 34

=> 178 - 34 = 4B

=> 144 = 4B

=> 144/4 = B

=> 36 = B

• The Breadth of the park is 36 m

Putting the value of B in equation (i).

=> L = B + 17

=> L = 36 + 17

=> L = 53

• The Length of the park is 53 m.

Hence, the length is 53 and breadth is 36 of the rectangular park.