Question

Example 62. Calculate the current shown by the ammeter
A in the circuit shown in Fig. 3.42.!!!!.please give me detailed answer ........ ​

Answer 1

Answer:

Your Answer is

Resistors of 5ohm and 5ohm are in parallel series

so,

1/Rp=1/R1+1/R2

1/Rp = 1/5+1/5

1/Rp=2/5

Rp=5/2

Rp=2.5ohm

Resistors of another pair of 10ohm and 10ohm are in series

So,

Rs=R1+R2

Rs=10+10

Rs=20ohm

Similarly another set of 10ohm and 10ohm are in series

So,

Rs=R1+R2

Rs=10+10

Rs=20ohm

We have found the total effective resistances of each combination.

And The equivalent resistance 2.5ohm, 20ohm and 20ohm are in Parallel.

So,

1/Rp=1/R1+1/R2+1R3

1/Rp=10/25+1/20+1/20

1/Rp=4+5+5/100

1/Rp=14/100

Rp=100/40ohm

To find out the current

We have to apply ohm's law

V=IR

I=V/R

I=10/100/40

I=10x40/100

I=4A

Hope it is helpful to you...