Question

Example 63. In the given circuit, with steady current,
calculate the potential difference across the capacitor and the
charge stored in it.

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Answer 1

Given:

The circuit with steady current.

To find:

In the given circuit, with steady current, calculate the potential difference across the capacitor and the charge stored in it.

Solution:

From given, we have,

Applying KVL in the loop ACDEFA, we get,

-12 + 2 × I + 1 × I + 6 = 0

-12 + 2I + I + 6 = 0

3I - 6 = 0

I = 2

Applying KVL in the loop BEDCB, we get,

Let the potential drop in the capacitor be Vc

Vc + 6 - 12 + 2 × 2 = 0

Vc - 6 + 4 = 0

Vc = 2 V

Charge on the capacitor,

Q = CV

= 5 × 10^{-6} × 2

= 10 × 10^{-6} C

Answer 2

Answer:

here's the answer of this question

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