EXAMPLE 69. Two capacitors of capacitances C =3 uF and =6uF arranged in series are connected in parallel with a third-capacitor Cz = 4 uF. The arrangement is connected to a 6.0 V battery. Calculate the total energy stored in the capacitors.
[CBSE Sample Paper 98]
{Provide the circuit diagram, if possible}
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Total energy stored =8.1×10^-5 Joule
Total Energy Stored is=(1/2)CV^2
in series connection,the effective capacitance is=
(1/C)=(1/C1)+(1/C2)
in parallel connection the effective capacitance is=C= C1+ C2.
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