Question

Example 7: 6 pipes are required to fill a tank in 1 hour 20 minutes. How long will it
take if only 5 pipes of the same type are used?​

Answer 1

Refer to the attachment for the solution :)

$\red{\sf {Detailed \: explanation \: of \: your \: question: }}$

As we know the question you asked is of the case of inverse proportion.

Here , in inverse proportion it simply means if we need to some work

and something we need is lesser to complete our work then we need more time to complete our work because the thing we need to complete the work faster isn't available .

So in case , we have lesser number of things we need then we take more time.

For example ,

your question if there are 6 pipes we took 1 hour 20 minutes which is we need 80 minutes,

Now , if there are only 5 Pipes then we need 1 hour 36 minutes , because there is less pipe so we need more time.

This is called inverse proportion/inverse variation.

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$\red{\sf {Extra \: Information: }}$

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What is Direct proportion/Direct Variation.

= > If the statement x and y are in same proportion can be also written as a and y are in direct variation.

Direct variation is having a equation

Which is ,

$x \: \alpha \: y$

Here , alpha sign tell us that x varies constantly to y

Which is ,

x = ky

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Now the related thing is about time, work ,and speed also.

Any example or question related to the number of workers and time taken to finish the work are of inverse variation. Similarly, there are some examples related to the time taken to cover a distance by a vehicle and it's uniform speed.

Anytime, in inverse variation we need to increase or decrease mainly time , and speed

Answer 2

question:

6 pipes are required to fill a tank in 1 hour 20 minutes. How long will it take if only 5 pipes of the same type are used?

solution:

$\purple{ \sf 96 \: mins}$

Given:

6 pipes are required to fill a tank in 1 hour 20 minutes.

To find:

How long will it take if only 5 pipes of the same type are used?

step by step explanation:

let the time taken to fill the tank be x

$\sf So,80 \times 6 = x \times 5$

$\sf x = \frac{80 \times 6}{5}$

$\sf x = \frac{480}{5}$

$\longrightarrow\underline{\underline{\red{\sf{x = 96}}}}$

Therefore:

the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.