Question

Example 7: In the given figure,
angle pqr=85
qrp=60; find Angle SQR+Angle SRQ​

Answer 1

Answer:

U hope it is help full

Step-by-step explanation:

We know, the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle

Hence,In given circle,

∠POR=2∠PQR

Therefore ∠POR=2×40

o

=80

o

Answer 2

Answer:

downwards

Step-by-step explanation:

Let us take an angle QOR :

In the ∆QOR:

Angle QOR + Angle QRO = Angle SQP

( sum of two interior angles of a triangle is equal opposite exterior angle)

Angle QOR + 60° = 85°

Angle QOR = 85°- 60°

Angle QOR = 25°

In ∆ QOR:

Angle QOR + Angle QRO + Angle OQR = 180°

( angle sum property of a triangle )

25° + 60° + Angle OQR = 180°

85° + Angle OQR = 180°

Angle OQR = 180° - 85°

Angle OQR= 95°

Angle OQR + Angle QOR = Angle SRO

( sum of two interior angles of a triangle is equal to opposite exterior angle of the triangle )

25° + 95°= Angle SRO

120° = Angle SRO

SQR/OQR = 95°

ORQ + SRO = SRQ

60° + 120° = 180°

Angle SQR + Angle SRQ = 95° + 180° = 275°