Question

EXAMPLE-7 The velocity of a body is given by v = (6 + 4)m/s. Calculate the displacement of the motion between t=1s to t=2s. Solution:
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Answer 1

Answer:

x=5t

2

+18t

(1)v=

dt

dx

=10t+18

att=2s,v=10×2+18=38m/s

(2)Average,velocity=

time

displacement

att=2,x=5(2)

2

+18×2=56m

t=3,x=5(3)

2

+18×3=99m

Averagevelocity=

3−2

99−56

=43 m/s