Question

Example 8.1 An object travels 16 m in 4 s
and then another 16 m in 2 s. What is
the average speed of the object?​

Answer 1

Answer:

16 m/s

Explanation:

AVERAGE SPEED = TOTAL DISTANCE / TOTAL TIME TAKEN

THEREFORE,

16 + 16

_______ = 32 / 2 = 16 m/s

2 + 2

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Answer 2

Answer:

Given :-

• An object travels 16 m in 4 seconds and then another 16 m in 2 seconds.

To Find :-

• What is the average speed of the object.

Formula Used :-

$\clubsuit$ Average Speed Formula :

$\mapsto \sf\boxed{\bold{\pink{Average\: Speed =\: \dfrac{Total\: Distance\: Travelled}{Total\: Time}}}}$

Solution :-

${\small{\bold{\purple{\underline{\leadsto\: In\: case\: of\: total\: distance\: travelled\: :-}}}}}$

Given :

• d₁ = 16 m
• d₂ = 16 m

Then,

$\implies \sf Total\: distance\: travelled =\: d_1 + d_2$

$\implies \sf Total\: distance\: travelled =\: 16 + 16$

$\implies \sf\bold{\green{Total\: distance\: travelled =\: 32\: m}}$

${\small{\bold{\purple{\underline{\leadsto\: In\: case\: of\: total\: time\: taken\: :-}}}}}$

Given :

• t₁ = 4 seconds
• t₂ = 2 seconds

Then,

$\implies \sf Total \: time\: taken =\: t_1 + t_2$

$\implies \sf Total\: time\: taken =\: 4 + 2$

$\implies \sf\bold{\green{Total\: time\: taken =\: 6\: seconds}}$

Now, we have to find the average speed of the object :

Given :

• Total distance travelled = 32 m
• Total time taken = 6 seconds

According to the question by using the formula we get,

$\longrightarrow \sf Average\: Speed =\: \dfrac{\cancel{32}}{\cancel{6}}$

$\longrightarrow \sf Average\: Speed =\: \dfrac{16}{3}$

$\longrightarrow \sf\bold{\red{Average\: Speed =\: 5.33\: m/s}}$

$\therefore$ The average speed of the object is 5.33 m/s.