Physics, asked by pkjeengar, 5 months ago

Example 8.2 The odometer of a car reads
2000 km at the start of a trip and
2400 km at the end of the trip. If the
trip took 8 h, calculate the average
speed of the car in km h and ms'​

Answers

Answered by jevelin
4

Answer:

50 km h-¹ or 13.9 m s-¹

Explanation:

distance covered by the car,

s=2400 km – 2000 km = 400 km

Time elapsed, t = 8 h

Average speed of the car is

Vav = s/t = 400km/8

=50 km h-¹

50 km/h x 1000m / 1km x 1h/3600s

= 13.9m s-¹

The average speed of the car is 50 km h-¹ or 13.9 m s-¹

Answered by divyanshugb
0

\huge {\green {\sf {\underline {\underline {Solution}}}:-}}

Distance travelled by the car,

s = 2400 km - 2000 km = 400 km

Time elapsed, t = 8 h

Average speed of the car is,

 v_{av} =  \frac{s}{t}  =  \frac{400 \: km}{8 \: h} \\   = 50 \: km \:   {h}^{ - 1} \\  = 50  \: \frac{km}{h}  \times  \frac{1000 \: m}{1 \: km}  \times  \frac{1 \: h}{3600 \: s} \\  = 13.9 \: m \:  {s}^{ - 1} \\ The \: average \: speed \: of \: the \: car \: 50 \: km \:  {h}^{ - 1} \: or \: 13.9 \: m \:  {s}^{ - 1}.

\large\color{coral}{I \: hope \: this \: answer \: will \: be \: helpful.}

\huge\dag\sf\orange{By \: Divyanshu}

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