Question

Example 8.5 A train starting from rest
attains a velocity of 72 km h in
5 minutes. Assuming that the
acceleration is uniform, find (i) the
acceleration and (ii) the distance
travelled by the train for attaining this
velocity.​

Answer 1

Explanation:

A=V-U/T

U =0(STARTING FROM REST)

V=72KM/HR

=72*5/18

20M/S

T=5 MIN=300 SEC

A=20-0/300

20/300

1/15 M/S^2

2) 2AS=V^2-U^2

2*1/15*S=400-0

S=400*15/2

=200/15

40/3 M

Answer 2

Answer:

initial velocity (u)=0

final velocity (v)= 72 km/h

=72×1000/3600

=20m/s

time (t)=5 min=300sec

a=v-u/t

a=20-0/300

a=1/15ms^-2

s=ut+1/2at^2

s=0×300+1/2×1/15×300×300

s=0+3000

s=3000m