Question

Example 8.5 A train starting from rest
attains a velocity of 72 km h- in
5 minutes. Assuming that the
acceleration is uniform, find (i) the
acceleration and (ii) the distance
travelled by the train for attaining this
velocity​

Answer 1

Answer:

Given :

Initial Velocity=u=0m/s

Final velocity= V= 72km/h

Time =5 min =5/60 h =1/12 h

acceleration=a=?

As we know that , a=v-u/t

⇒a=72-0/1/12

=72*12

=864km/h²

Distance travelled  =s=ut+1/2at²

=0x1/12 +1/2(864)(1/12)²

=(1/2)x864x(1/144)

=3km

∴Distance travelled by the train for attaining this velocity 3km.