Example 8.5 A train starting from rest attains a velocity of 72 km - in 5 minutes. Assuming that the acceleration is uniform, find the acceleration and (ii) the distance travelled by the train for attaining this velocity
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Answer:
Hence the acceleration is 864km/h2.
Now, the distance travelled by train:
Formula used:
s=ut+12at2=0×112+12(864)(112)2=12×864×1144=3km
Explanation:
Ans 3 km
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