Example 8.6(A car accelerates uniformly
from 18 km h to 36 km h in 5 s.
Calculate (i) the acceleration and (ii) the
distance covered by the car in that time.
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Explanation:
v=36km h
u=18km h
v=10m s
u=5m s
a= v-u/t
a=10-5/5=1m/s2
distance=25 +12.5=37.5m
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