Question

Example 8.7 The brakes applied to a car
produce an acceleration of 6 m s2 in
the opposite direction to the motion. If
the car takes 2 s to stop after the
application of brakes, calculate the
distance it travels during this time.​

Answer 1

Answer:

Given,

a = - 6ms^-2

t = 2 sec

v = 0 m sec ( as the car stops)

Let

u = initial velocity of the car

Now,

v = u + at

u = v-at

u = 0 - (-6 × 2)

u = 12 m/s

s = ut + 1/2 at^2

s = 12×2+ 1/2×(-6)(2)^2

s = 24 +(-3)(4)

s = 24 - 12

s = 12m

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