Question

Example 8.7 The brakes applied to a car produce an acceleration of 6 m s-2 in the opposite direction to the motion. If the car takes 2 s to stop after the application of brakes, calculate the distance it travels during this time.​

Answer 1

Answer:

Given:

Accerleration: a=−6 m/s

2

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+

2

1

at

2

s=12×2+

2

1

×(−6)×4

⇒s=12 m

Answer 2

Hello Dear Student,

Here is your answer:-

12m

Explanation:-

Given:

Accerleration: a=−6 m/$s^{2}$  

 

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+ 1/2 a$t^{2}$

s=12×2+1/2×(−6)×4

s=12

Thank You