Question

Example 8: Raju painted the outside of a
cabinet on all sides except the bottom. If the
cabinet measures 2 m x 1 m 1.5 m, how much
surface did he paint?​

Answer 1

Assuming the cabinet to be a cuboid since it's tridimensional

length = 2 m

breadth = 1 m

height = 1.5 m

Surface area of a cuboid = 2 (lb+bh+lh)

= 2(2×1+1×1.5+2×1.5)

= 2 (2+1.5+3)

= 2(6.5)

= 13.0

Area of a rectangle = lb

= 2 × 1

= 2 m

Area painted = 13 - 2

= 11 m

I think it's correct

:-)

Answer 2

GIVEN :-

• Length of cabinet = 2m

• Breath of cabinet = 1m

• Height of cabinet = 1.5m

TO FIND :-

• Surface did raju paint.

SOLUTION :-

We know that,

Now,

⟶ Area painted by raju = 2lh + 2bh + lb.

[ Put the values ]

⟶ Area painted by raju = 2( 2×1.5) + 2(1×1.5) + (2×1)

⟶ Area of painted by raju = 6 + 3 + 2

⟶ Area of painted by raju = 11m².

Therefore, the area painted by raju is 11m².