Physics, asked by dipanjalijoshi0417, 6 months ago

Example 80. A generator develops an emf of 120 V and has
a terminal potential difference of 115 V, when the armature
current is 25 A. What is the resistance of the armature ?​

Answers

Answered by LoverLoser
23

\small{\underline{\sf{\red{Given:\rightarrow}}}}

  • \bf{E = 120 V, V = 115 V, I = 25 A}

\small{\underline{\sf{\pink{Find:\rightarrow}}}}

  • \bf{resistance}

\small{\underline{\sf{\blue{Formula \ used:\rightarrow}}}}

  • \boxed{\bf{\orange{I= \dfrac{E-V}{R}}}}

\sf{where, I = current; R= Resistance; V= Voltage \ and}

\sf{ E= emf}

\small{\underline{\sf{\green{Formula \ used:\rightarrow}}}}

\sf{Putting \ all\ values\ in\ formula}

\sf{R= \dfrac{120-115}{25}= \dfrac{5}{25} = \dfrac{1}{5}= 0.2\Omega }

\bf{\underline{ \therefore Resistance\ of\ armature \ is\  0.2\ \Omega.}}

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