Physics, asked by anant363, 11 months ago

EXAMPLE 81. If R is the horizontal range for 0 inclination
and h is the maximum height reached by the projectile, show
that the maximum range is given by a R^2/8h. +. 2h​

Answers

Answered by kashu77
5

Explanation:

maximum height can be attained only when the projectile is launched at 90°

threrfore ,

h= u^2/2g

25×2×9.8= u^2

490=u^2

7√10=u

then for range ,

the maximum range occurs at 45°

R = u^2/g

R = 490/9.8

R = 50 m

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