EXAMPLE 84. The percentage errors in the measurement of
mass and speed are 2% and 3% respectively. How much will
be the maximum error in the estimate of kinetic energy
obtained by measuring mass and speed ?
INCERT]
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Solution :-
As per the given data ,
- % error in mass (m) = 2 % = 2 / 100
- % error in speed (v)= 3 % = 3 / 100
Kinetic energy is the energy possesed by an object due to it's motion .
Kinetic energy is given by the formula ,
➜ KE = mv² / 2
Now ,
% error in kinetic energy is given by ,
➜ Δ KE / KE = ± ( Δ m /m + 2 Δv / v )
Now let's substitute the given values in the above equation ,
➜ Δ KE / KE = ± ( 2 / 100 + 2 x 3 / 100)
➜ Δ KE / KE = ± ( 2 / 100 + 6 / 100 )
➜ Δ KE / KE = ± ( 8 / 100 )
➜ Δ KE / KE = ± 8 %
The maximum error in the estimate of kinetic energy obtained is 8 %
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