Example 9.6 A bullet of mass 20 g is
horizontally fired with a velocity
150 m s' from a pistol of mass 2 kg.
What is the recoil velocity of the pistol?
Answers
Answered by
28
Answer:
Step-by-step explanation:
mass1=0.02kg
u1=0m/s
v1=150m/s
mass2=2kg
u2=0m/s
v2=v.
∴by the law of conservation of momentum,
m1u1+m2u2=m1v1+m2v2
0.02*0+2*0=0.02*150+2*v
⇒0+0=3+2v
⇒3=2v
⇒3/2=v
⇒1.5=v
∴recoil velocity = 1.5 m/s
Answered by
11
Answer:
pls mark as brainliest ☺️
Attachments:
Similar questions