Question

Example 9.6 A bullet of mass 20
horizontally fired with a
150 m s. from a pistol of mass 2 kg.
What is the recoil velocity of the pistol?
g is
velocity​

Answer 1

Answer:

1.5 m/s in direction opposite to the velocity of bullet

Explanation:

Consider law of conservation of momentum

m1u1 +m2u2 = m1v1 +m2v2

considering mass in gms

20(0) +2000(0) = 20(150)+ 2000(V2)

0= 3000 + 2000 ( V2)

V2 = -3000/2000

= - 1.5

here 1.5 is magnitude and - is the direction

Answer 2

v2=v. Let v be the recoil velocity of the pistol. Thus, the recoil velocity of the pistol is 1.5 m/s.