Example 9 : The diameter of a wheel is 28 cm.
It rolls through a distance of 22 meters. How many
revolutions will it make?
Answers
Answer:
tThe coulomb force between two charges q1, q2 is:
F =kq1q2/r^2
k = coulomb’s constant = 1/4πεε0
ε0 = permittivity of empty space
ε = relative permittivity of the material in which the charges are immersed
r = distance between charges
for vacuum ε=1 and for air also, to a very good approximation ε=1.
For water , at room temperature ( 20C) ε = 80.
Therefore, the force between the charges q1, q2 will be 1/80 its value in air.
Hence Fw, the force in water will be:
Fw = 80/80 = 1N.
Step-by-step explanation:
=> Given diameter of a wheel =28cm
=> Radius is = 14cm
=> Circumference of wheel = 2πr
=> Distance travelled in one revolution = 2 × π × 14
=> Total distance = 22m = 2200cm
=> So, number of revolution make by wheel = 2200/28π = 25
I hope this will help you dear..
Always stay safe and stay healthy..