Question

Example 9: The dimensions of a rectangular field are 90 m and 60 m. Two roads are
constructed such that they cut each other at the centre of the field and are parallel
to its sides. If the width of each road is 3 m, find-
(i) The area covered by the roads.
(ii) The cost of constructing the roads at the rate of 110 per m².​

Answer 1

Answer:

Step-by-step explanation:

Area of roads = (90 x 3) + (60 x 3) - (3 - 3)

                       = 441

Cost of cunstruction = 441 x 110

                                  = 48,510

Answer 2

Answer:

1) Area of roads=(90×3)+(60×3)-(3×3)

=270+180-9=441m²

2) Cost of construction=441×110=₹48510

Hope it helps... Please mark me as brainliest...!