Example 91. If two resistors of resistances R, = (4 *0.5)2
and R, =(16 +0.5) are connected (i) in series and (ii) in
parallel: find the equivalent resistance in each case with
limits of percentage error.
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Answer:
i)R=18.5 ii)R=66/37
Explanation:
Rs=R1+R2
=2+16.5
=18.5
Rp=R1R2/R1+R2
=2(16.5)/2+16.5
=33/18.5
=330/185
=66/37
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