Question

Example 91. If two resistors of resistances R, = (4 *0.5)2
and R, =(16 +0.5) are connected (i) in series and (ii) in
parallel: find the equivalent resistance in each case with
limits of percentage error.​

Answer 1

PLZ MARK AS BRILLIANT ❣️

$\color{red}PLZ \:THANK$

Answer 2

Answer:

i)R=18.5 ii)R=66/37

Explanation:

Rs=R1+R2

=2+16.5

=18.5

Rp=R1R2/R1+R2

=2(16.5)/2+16.5

=33/18.5

=330/185

=66/37