Question

Example a block of lead 25 mm x 25 mm x 150 mm is pressed between flat dies to a size 6.25 mm x 100 mm x 150 mm. If the uniaxial flow stress is (jo = 6.9 mpa and /l = 0.25 determine the pressure distribution over the 100 mm dimension and the total forging load.

Answer 1

The correct answer of pressure distribution is 58.9 & 8.0 MPa.

Explanation:

• This is calculated using the formula p = σy = Y'$e^{2u(a-x)lh}$

• Now replace this with values we get 435MPa.

• To find the forging load, one has to use the formula given below.

• Forging load = stress x area.

• Replacing this equation with values, we get (39.8 x $10^{6}$) (100 x $10^{-3}$) (150 x $10^{-3}$)

• Hence forging load becomes 597 kN.