Question

Example - A car moves the 1st half of the distaoce a
between two places at a speed of 40 kmhr
and the and half at 60kmh. What is the
average speed of the car?​

Answer 1

Answer:

Car moves with 40 km/hr for half distance and 60km/hr with another half distance. We need to find out the average speed of the car.

First of all, we need to remember the definition of average speed : It's the ratio of total distance to the total time taken to cover that distance.

Calculation:

$\bigstar \: avg. \: v = \dfrac{total \: distance}{total \: time}$

$= > avg. \: v = \dfrac{d}{ (\dfrac{ \frac{d}{2} }{40}) + (\dfrac{ \frac{d}{2} }{40} ) }$

Cancelling the similar term :

$= > avg. \: v = \dfrac{2}{ \frac{1}{40} + \frac{1}{60} }$

$= > avg. \: v = \dfrac{2}{ ( \frac{40 + 60}{40 \times 60} )}$

$= > avg. \: v = \dfrac{2 \times 40 \times 60}{100}$

$= > avg. \: v = 48 \: km {hr}^{ - 1}$

So final answer is:

Average speed is 48 km/hr

Answer 2

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QUESTION :

Example - A car moves the 1st half of the distaoce a

Example - A car moves the 1st half of the distaoce abetween two places at a speed of 40 kmhr and the and half at 60kmh.

What is the average speed of the car?

SOLUTION :

From the question, the following information can be obtained.....

- A car moves the 1st half of the distaoce a

- A car moves the 1st half of the distaoce abetween two places at a speed of 40 kmhr and the and half at 60kmh.

Let the total distance travelled by the car = 2 d

S = d / t

t = S / d

Average Velocity = Total distance travelled / Total time taken

=>2 d / { d / 40 } + { d / 60 } = 48 kmph.

Answer :

The average Velocity of the car is 48 kmph.