Example
A solid hemisphere of radius 6 cm is melted to form a rod of length 12 cm. Find
the radius of the cross section of the rod.
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Step-by-step explanation:
hence the radius of the rod is 2root6
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The radius of the cross section is 2√3 cm.
- A solid hemisphere is given as 6cm and is melted into a rod of length 12 cm.
- We have to find the radius of cross section of the rod.
- Volume of the hemisphere will be equal to the volume of rod.
- The shape of the rod is a cylinder with length of rod equal to height of the cylinder.
Volume of hemisphere = Volume of rod,
- Given radius of sphere is 6 cm and height of the rod is 12 cm.
Substituting the values we get,
(2/3)πr³ = πr²h
(2/3)×6³ = r²×12
r² = 12
r = 2√3 cm.
- Radius of cross section is 2√3 cm.
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