Example
A stone is dropped by a person from the top of a building, which is 200 m tall. At the same time, another
stone is thrown upwards, with a velocity of 50 m s'by a person standing at the foot of the building. Find
the time after which the two stones meet.
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For stone B,u=40m/s,a=9.8m/s2. 200=40t,t=20040=5sec. From (ii), h=40×5-4.9(5)2=200-122.5=77.5m
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