Question

* Example, consider a series circuit which
consists of three resistors with resistance
5ohm ,10ohm5ohm
respectively with a
15 v battery. Find the equivalent resis
tance of the circuit,​

Answer 1

Answer:

Answer

In this circuit, 8Ω and 12Ω are connected in parallel, and this parallel resistors are connected in series with 7.2Ω.

8Ω and 12Ω are in parallel, their equivalent resistance:

R

1

=

8

1

+

12

1

=

24

5

R=4.8Ω

Now, Equivalent resistance (series connection) of the circuit =4.8+7.2=12Ω

V=IR

eq

I=

R

eq

V

=

12

6

=0.5A

Potential Difference across 7.2Ω resistor =I×R=0.5×7.2=3.6V