Question

* Example, consider a series circuit which
consists of three resistors with resistance
5ohm ,10ohm5ohm
respectively with a
15 v battery. Find the equivalent resis
tance of the circuit,​

Answer 1

Step-by-step explanation:

R = R1 + R2 + R3 = 30Ω

I = V/R = 30 / 30 = 1A

V across 10Ω = IR2 = 1 × 10 = 10 V

Answer 2

Answer:

• 20 ohm is the required Answer .

Given:-

• Resistance of 1st Resistor ,R1 = 5 ohm
• Resistance of 2nd Resistor ,R2 = 10 ohm
• Resistance of 3rd Resistor ,R3 = 5 ohm

To Find:-

• Equivalent Resistance ,Req

Solution:-

As we have to calculate the Equivalent Resistance of Resistor which are connected in series.

Equivalent Resistance in Series is calculated by the sum of resistance of each individual Resistors.

• Req = R1 + R2 + R3 + ...

Where,

• Req denote Equivalent Resistance
• R1 denote resistance of 1st Resistor
• R2 denote Resistance of 2nd Resistor
• R3 denote Resistance of 3rd Resistor

Substitute the value we get

→ Req = 5Ω + 10Ω + 5Ω

→ Req = 20Ω

• Hence, the equivalent resistance in the series combination of given Resistor is 20 ohm.