Question

Example: Find the HCF of 126 and 540 by long division method.
Step 1:
12'615404
Divide the greater number by the smaller number.
540 - 126; Q→ 4, R → 36
Divide the first divisor by the first remainder.
126 = 36; Q→ 3, R – 18
Step 2:
-504
36|1263
-108
Step 3:
(1 813
Step 4:
Divide the second divisor by the second remainder.
36 = 18; Q→ 2, R → 0
The divisor which does not leave a remainder
is the HCF of the given numbers.
Hence, the HCF of 126 and 540 is 18.
HCF
Exercise 6.3
1. Find the HCF of the following using the short division method.
a 150, 300, 396
b. 81, 405
c. 630, 1260
d. 324, 378, 1890
e. 24, 112, 672
K 98,588, 1764
g, 116, 290, 580
h. 240, 1680
i., 175, 1225, 3€
2. Find the HCF of the following using the long division method​

Answer 1

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